Every line segment is an altitude, namely BD, AB, BC for triangle ABC (angle B is a right-angle) BD, AD are altitudes for triangle ABD BD, DC are altitudes for triangle BDC So in all, altitudes are BD,AB, BC,AD,DC.
Using metric relations, BD^2=AD*DC=5*7=35 => BD=sqrt(35)=5.916 (to 3 decimal places)
Hence the area of triangle ABC Area=Base*Height/2 = (5+7)*sqrt(35)/2= 35.496 (to 3 decimal places)
