maddylm9 maddylm9

02-02-2018
Mathematics

contestada

Factor completely. 49 t6 - 4 k8

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choixongdong choixongdong

02-02-2018

49 t^6 - 4 k^8
= (7t^3)^2 - (2k^4)^2
= (7t^3 + 2k^4)(7t^3 - 2k^4)

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