we have
[tex] 2.25 - 11j - 7.75+ 1.5j = 0.5j - 1 [/tex]
Solve for j
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex] 2.25 - 11j - 7.75+ 1.5j = 0.5j - 1\\ 11j+0.5j-1.5j=2.25-7.75+1\\ 10j=- 4.5\\\\ j= -\frac{4.5}{10} \\ \\ j=-0.45 [/tex]
therefore
the answer is
[tex] j=-0.45 [/tex]