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What is the electric potential energy of an arrangement of two charges, -14.88 μC and -23 μC, separated by 34.35 cm?

Respuesta :

[tex]\begin{gathered} E=\frac{kQq}{r} \\ E=\frac{8.98\cdot10^9\cdot14.88\cdot10^{-6}\cdot23\cdot10^{-6}}{.3435}=-8.95J \end{gathered}[/tex]

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