At time t, the position is x(t) = 0.5t3 - 3t2 + 3t + 2.
To find the position:
The derivative of x with respect to t is zero when the velocity is zero. That is to say,
Use the quadratic formula to solve.
When t =0.5858 s, the position is:
When t=3.4142 s, the position is:
Reject the negative answer.
So, when t = 0.586 s, the velocity is zero and the distance is 2.83 m.
The second derivative of x with respect to t is zero when the acceleration is zero.
That is to say,
The distance traveled is:
So, when the acceleration is zero, t = 2 s, and the distance traveled is zero.
Therefore, at time t, the position is x(t) = 0.5t3 - 3t2 + 3t + 2.
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The correct question is given below:
A girl operates a radio-controlled model car in a vacant parking lot. the girl’s position is at the origin of the XY coordinate axes, and the surface of the parking lot lies in the XY plane. she drives the car in a straight line so that the x coordinate is defined by the relation x(t) = 0.5t3 - 3t2 + 3t + 2 where x and t are expressed in meters and seconds, respectively. determine when the velocity is 0 m/s, and the position and the total distance traveled when the acceleration is zero.