The sum of three numbers is 123. The third number is 4 times the first. The second number is 9 more than the first. What are the numbers?

Answer:
1st = 19
2nd = 76
3rd = 28
Step-by-step explanation:
n + 4n + n + 9 = 123
6n + 9 = 123
6n = 114
n = 19
4(19) = 76
(19) + 9 = 28
Hope this helps :)