PLEASE HELP! Two years ago a man was six times as old as his daughter. In 18 years he will be twice as old as his daughter. Determine their present ages.
Two years ago a man was six times as old as his daughter. m- 2 = 6(d-2) m - 2 = 6d - 12 m = 6d - 12 + 2 m = 6d - 10 : In 18 years he will be twice as old as his daughter. m + 18 = 2(d+18) m + 18 = 2d + 36 m = 2d + 36 - 18 m = d + 18 From the 1st equation, replace m with (6d-10) 6d - 10 = 2d + 18 6d - 2d = 18 + 10 4d = 28 d = 28/4 d = 7 yrs is the daughter's age Find Dad's age m = 6(7) - 10 m = 42 - 10 m = 32 yrs is Dad's age : : Check solutions in the statement: "In 18 years he will be twice as old as his daughter." 32 + 18 = 2(7 + 18) 50 = 2(25)
